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KMnO, reacts with oxalic acid according to the equation,
2MnO, +5C,0 +16H 2Mn+ +1000, +8H,0, here
20 ml of 0.1 M KMnO4 is equivalent to [CBSE PMT 1996]
(a) 20 mL of 0.5 M HOC204
(b) 50 mL of 0.1 M H2C,04
(e) 50 mL of 0.5 M H.C.04
(d) 20 mL of 0.1 M HỌC204
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Answer:
It's too simple dear....
Explanation:
Hey send your question again... It's not too clear to me.... So many comma's.....
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