27 mercury drops coalease to form a bigger drop if Potential on small drops is 10V then Potential on larger dropi. is ??
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Answer:
Substitute the value of potential for 27 small drops in it and find the potential of large drops formed due to combining 27 small drops. Hence, the potential of the large drop will be 90V. So, the correct answer is “Option B”.
Explanation:
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Explanation:
Voltage of each mercury drop =10V
⇒rkq=10V⇒q=k10rtotal charge=k27×10r
Equating volumes to find radius of bigger charge,
34π(R3)=27⋅34πr3R=3r
final voltage=Rkq=k×3rk×27×10r=90V
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