Physics, asked by fcilrathore2004, 1 month ago

27 mercury drops coalease to form a bigger drop if Potential on small drops is 10V then Potential on larger dropi. is ??​

Answers

Answered by satvinderrana911
0

Answer:

Substitute the value of potential for 27 small drops in it and find the potential of large drops formed due to combining 27 small drops. Hence, the potential of the large drop will be 90V. So, the correct answer is “Option B”.

Explanation:

☺☺☺

Answered by mohnishkrishna05
0

Answer:

mark me as brainliest and thank me if the answer is useful.

Explanation:

Voltage of each mercury drop =10V

⇒rkq​=10V⇒q=k10r​total charge=k27×10r​

Equating volumes to find radius of bigger charge,

34​π(R3)=27⋅34​πr3R=3r

final voltage=Rkq​=k×3rk×27×10r​=90V

Similar questions