Question

27 of Al is reacted with 32 g of O2
& al2o3 formed in the reaction
to following reaction is ?
4 Al + 3O2 - Al2O3​

Answer 1

Answer:

51 g of Al formed

Explanation:

4Al+3O2----->2Al2O3

1 mole of Al is given(27/27)

1 mole of O2 is also given.

4 moles of Al require 3 moles of O2 to form 2 moles of Al2O3.

1 mole of Al will require 3/4 moles of O2 and will form 2/4 moles of Al2O3.

3*32/4 g of O2 will react= 24g

Left=8g

Al203 formed=2*102/4

=51g of Al203 formed.