Question

27. Percentage error in the measurements (4 +0.2) m is
(1) 0.5%
(2) 0.05%
(3) 5%
(4) 50%​

Answer 1

Answer:

5%

Explanation:

error=0.2

value=4

%error=error/value×100

=0.2/4×100

=1/20×100

=5%