Question

27. (PISA) :
Below you see a student's mathematical model of a
farmhouse roof with measurements. The attic floor,
ABCD in the model, is a square. The beams that
support the roof are the edges of a rectangular prism,
EFGHKLMN. E is the middle of AT, F is the middle
of BT, G is the middle of CT, and H is the middle of
DT. All the edges of the pyramid in the model have
length of 12 m
Calculate the area of the attic floor ABCD.
The area of the attic floor ABCD = -------- m
12m
b)
Calculate the length of EF, one of the
horizontal edges of the block.
VIF
-4 --4--------
N 1 M
Itt-tz
1
X
The length of EF = --------------- m
KLU
12m
12m
B​

Answer 1

Area of the attic floor ABCD. = 144 m² , The length of EF  = 6 m

Step-by-step explanation:

For complete Question see attached picture

area of the attic floor ABCD. = AB * BC

= 12 * 12

= 144 m²

Area of the attic floor ABCD. = 144 m²

E is the middle of AT  => ET = AT/2 = 6 m

F is the middle of BT  => FT = BT/2 = 6 m

ΔTEF ≈ ΔTAB

=> ET/AT  = FT/BT  =  EF/AB

=> 6/12 = 6/12 = EF/12

=> EF = 6 m

The length of EF  = 6 m

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Answer 2

Answer:

hope this answer will help you.