Question

27) Show that, tan²0 + cot0 + 2 = sec @cosec0
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Answer 1

Answer:

(tanθ+cotθ)

2

=sec

2

θ+cosec

2

θ

L.H.S (tanθ+cotθ)

2

=tan

2

θ+cot

2

θ+2tanθcotθ

=sec

2

θ−1+cosec

2

θ−1+2tanθ

tanθ

1

=sec

2

θ+cosec

2

θ−2+2

=sec

2

θ+cosec

2

θ

=R.H.S.