Question

27. Show that the trajectory of a projectile is a parabola.​

Answer 1

Answer:

Equation (5) represents the path of the projectile. If we put tan θ = A and g/2u2cos2θ = B then equation (5) can be written as y = Ax - Bx2 where A and B are constants. This is the equation of a parabola. Hence, the path of the projectile is a parabola.

Explanation:

Answer 2

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The Question is Give below

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The horizontal component remains constant while the vertical component is affected by gravity. a = tan θ, b = y=gas−bx22u2cos2θ, are constants for given values of θ, u and g.

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