27 solid iron spheres each of radius 7 cm are melted to form a new sphere find the surface area and volume of new sphere
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ATQ, 27 solid iron spheres each of radius 7 cm are melted to form a new sphere. we have to find the surface area and volume of the new sphere.
volume of the sphere of radius 7cm = 4/3πr³
= 4/3 × 22/7 × 7 × 7 × 7
= 88/3 × 7 × 7
= 4312/3cm³
therefore total volume of 27 such spheres = 4312/3 × 27
= 116424/3
= 38808cm³
hence, the volume of the new sphere is 38808cm³
to find it's radius,
=> 4/3πr³ = 38808cm³
=> 4/3 × 22/7 × r³ = 38808cm³
=> 88/21 × r³ = 38808cm³
=> r³ = 38808/1 × 21/88
=> r³ = 441 × 21
=> r³ = 9261
=> r = ³√9261
=> r = ³√(21 × 21 × 21)
=> r = 21cm
now, TSA (total surface area) of the sphere = 4πr²
= 4 × 22/7 × 21 × 21
= 88 × 3 × 21
= 5544cm²
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