Question

27 solid iron spheres each of radius r 2cm are melted to form a new solid sphere what will be the sa of the new sphere

Answer 1

Answer:

144π

Step-by-step explanation:

$27 \times \frac{4}{3} \pi \times {r}^{3} = \frac{4}{3} \pi \times {r}^{3} \\ 27 \times {r}^{3} = {r}^{3} \\ \sqrt[3]{27 \times {r}^{3} } = r \\ 3 \times r = r \\ (r = 2) \\ 3 \times 2 = r \\ 6 = r \\ surface \: area = 4\pi {r}^{2} \\ = 4\pi \times {6}^{2} \\ = 4\pi \times 36 \\ = 144\pi$