Question

27 solid iron spheres each of radius R and surface area S are melted to form a sphere of surface area S'. find the i radius r' of the new sphere ii ratio of S and S'​

Answer 1

Step-by-step explanation:

(I) ==>> radius of one solid iron sphere=r

==>>>volume = 4 by 3 pi r cube.

===>> volume of twenty seven solid iron spheres =27 into 4 by 3 pi r cube.

===>> 4/3 πr'³ = 27×4/3πr³

===>> r'³ = 2πr³

===>> r'³ = 3r.

(ii) surface area= 4πr²

==>> Sπr'=4πr'²

===>> 4π {3r}² = 36πr²

==>>S/S' = 4πr²/36πr³

==>> 1/9 ==>> 1:9

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