Question

27. Solve for x : 9x2 – 9(a+b)x + 2a2 +5ab + 2b2 = 0

Answer 1

Shridharacharya Method

Shridharacharya method which is also called quadric formula is used to find out toughest factors of x in a quadratic polynomial.

• According to formula,

x = (- b +/- √D)/2a where D = b² - 4ac.

• In polynomial, 9x² - 9(a + b) + 2a² + 5ab + 2b²

1. a = 9
2. b = - 9(a + b)
3. c = 2a² + 5ab + 2b²

• Since value will come in +/- which means that, factors obtained are distinct.

• Identities used :

1. (a + b)² = a² + 2ab + b²
2. (a - b)² = a² - 2ab + b²