27 spherical droplets each of radius 3mm and carrying 10 to the power minu 12c of charge are combined to form a single drop. find the capacitance and potential of the bigger drop
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GIVEN:
- Number of droplets, n = 27
- Radius of single droplet, r = 3mm = 3 × 10^-3 m
- Charge of single droplet, q = 10^-12 C
TO FIND:
- Capacitance of bigger drop, C
- Potential of bigger drop, V
FORMULAE:
- Volume of spherical droplets = (4πr³) / 3
- Capacitance, C = 4πr
- Potential, V = Q / C
where, is the permittivity of free space and is equal to 8.854 × 10^-12 C^2 N^-2 m^-2
SOLUTION:
STEP 1:
- 27 spherical droplets combine to form large single droplet.
- According to law of conservation of charges, total charge remains constant.
- Total charges of individual droplets = Charge of single big droplets
- Q = nq : where Q is the charge of bigger droplet and q is the charge of single small droplet.
Q = nq
Q = 27 × 10^-12 C
STEP 2:
- Let R be the radius of bigger droplet and r be the radius of single small droplet.
- Volume remains constant before and after the combination of droplets.
- Volume of bigger droplet = Total volume of smaller droplets.
(4πR³)/3 = n × (4πr³)/3
R³ = n r³
n = R³/r³
n = (R /r )³
27 = (R / r )³
3³ = (R / r )³
3 = R / r
R = 3r
R = 3 × 3× 10^-3
R = 9 × 10^-3 m
STEP 3:
Let C be the capacitance of bigger droplet .
Capacitance of bigger droplet , C = 4πR
STEP 4 :
Let V be the potential of bigger droplet.
ANSWER:
- Capacitance of bigger droplet is 1000.856 × 10^-15 F
- Potential of bigger droplet is 26.9 volt
Answered by
0
- Capacitance of bigger droplet is 1000.856 × 10-¹⁵ F
- Potential of bigger droplet is 26.9 volt
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