27. Sum of the digits of a two-digit number is 11. The given number is less than the number
obtained by interchanging the digits by 9. Find the number.
note:(please solve in one variable)
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You rlly dont know how to do this you should have a same pn yourself
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Answer:
let one's digit=x
& ten's digit=11-x
Original no. =10(11-x)+x
=110-10x+x
=110-9x
On interchanging the digits,we get
One's digit=11-x
Ten's digit=x
New no. =10×x+11-x
=10x+11-x
=9x+11
A/Q
(9x+11)-(110-9x)=9
9x+11-110+9x=9
18x-99=9
18x=9+99
x=108/18
x=6
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