(27)
power of root
root of power
cube root of 4th power of 64
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Answer:
Step-by-step explanation:
Correct option is
C
7
xy
x+y
=
2007
1
⇒xy−2007(x+y)=0
Adding 2007
2
to both sides, we get
xy−2007(x+y)+2007
2
=2007
2
⇒(x−2007)(y−2007)=2007
2
Let x−2007=A and y−2007=B
The equation becomes AB=2007
2
Number of solutions of above equation is equal to number of factors of 2007
2
2007
2
=3
4
×223
2
Hence, number of factors of 2007
2
is (4+1)(2+1)=15
In one case A=B=2007
Of the remaining 14 cases, half of the case A>B and remaining half A<B
Accordingly we get 7 cases, where x<y.
Video Explanation
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