Question

27. The base of a parallelogram is
(p+4). Altitude to the base is (p−3) and the area is (p²−4).
Find out its actual area.​

Answer 1

Step-by-step explanation:

p^2-4=(p+4)×(p-3)

=p^2-3p+4p-12

-4=-3p+4p-12

-4+12=p

p=8

area=p^2-4=8^2-4=60

Hope this was useful...

Answer 2

Answer = 60 Square unit

Refer formula for parallelogram

area = base × height

$\bf \red{Therefore, }$

${p}^{2} - 4 = (p + 4)(p - 3)$

$⟹ {p}^{2} - 4 = {p}^{2} + p - 12$

$⟹p = 18$

$\bf \red{Hence, }Actual \: area$

$⟹( {p}^{2} - 4) = {8}^{2} - 4 = 60 \: sq. \: units.$