Question

27. The equation of a state for 5 gram of oxygen at a pressure P and temperature T, when occupying a volume
V will be
(A) PV=5RT/32
(B) PV=SRT/16
(C) PV=(5/2)RT
(D) PV=5RT​

Answer 1

Answer:

According to Ideal gas equation

PV= nRT where P =pressure; V= volume; n= number of moles; R= gas constant; T= temperature(kelvin)

Also

number of moles (n)= total mass/Molar mass

Thus the ideal gas equation can be written as

PV= (m/M) RT

Here total mass = 5 g (given) and

molar mass of (O) = 16

Oxygen O2 = 16 × 2= 32

PV= (5/32) RT.

Answer 2

Explanation:

this is the correct answer