Question

27. The LCM of (16 - x2) and (x2 + x - 6) is
(a) (x - 3)(x + 3) (4 - x2)
(b) 4(4 - x2)(x + 3)
(c) (4 - x2)(x - 3)
(d) (16 - x2) (x - 2)(x + 3)​

Answer 1

Step-by-step explanation:

16 =4^2

we can write the LHS side as (4^2 - x^2) which one factorisation process can be written as

(4+x) (4-x)

similarly x2+x-6 when

= x^2+3x-2x-6

=x(x+3) -2(x+3)

=(x+3) (x+2)

in both LHS side and RHS side no term is common, the LCM will be the multiplication of all the given equation