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The LCM of two numbers is 168 and their HCF is 12. If the difference between the numbers is 60. what is the sum of
the numbers
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Answered by
32
LCM * HCF = Product of number
168 * 12 = x*y
x - y = 60
x + y = √(x-y)^2 - 4xy
x + y = √(60)^2 - 4 * 68 * 12
x + y = 108
hope it helped you
Answered by
29
Answer:
The sum of the two numbers is 108.
Step-by-step explanation:
Product of HCF and LCM of two numbers is equal to the product of the two numbers.
Let, the numbers are a and b.,
a.b = l. g
a x b = 168 x 12 = 2016 and
a - b = 60 ( Given )
( a + b )^2 = ( a - b )^2 + 4ab
= (60 )^2 + 4 ( 2016 )
= 3600 + 8064
= 11664
( a + b ) = √ 11664
= √2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3
=2 x2 x 3 x 3 x 3
=108
( a + b ) = 108
The sum of the two numbers is 108.
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