Question

27. The power developed by a 50 kg boy when moving with a velocity of 2 ms- upwards in direction making an angle of 60° with the vertical is
A) 980 W
B) 490 W
C) 245 W​

Answer 1

Answer:

490 W

Explanation:

P=F. S = FScos60 = 50(9.8) * 1/2 = 490 W

Answer 2

Answer:

$490 \sqrt{3}$