27. The value of (2a - 5b).' + (5b - 7c)2 + (7c - 2a)"
is
(A) 3(2a - 56) (5b-7c) (7c - 2a)
(B) 6(2a - 56) (5b - 7c) (7c - 2a)
(C) 4(2a + 5b) (5b - 7c) (7c + 2a)
(D) 12(2a - 5b) (55-7c) (7c - 2a)
Answers
Answer:
Starting with the second given equation;
3a + 5b + 7c = 30
(2a + 3b + 4c) + (a + 2b + 3c) = 30
35 + (a + 2b + 3c) = 30
a + 2b + 3c = -5______(1)
Now, using the first equation
2a + 3b + 4c = 35
( a + 2b + 3c) + (a + b + c)=35
-5 +(a + b + c)=35 [ using__(1)]
a + b +c=40
I need to solve for the three unknowns a, b, and c in the following equations. 3a - 5c = -9, 2a + 7b = 11, a + b + c = 6. The answer is (2, 1, 3), but how do I get there?
What are a, b, and c if 2a + 3b + 4c = 10?
If 3a+2b+4c=26 and 6b+4a+2c=48, then how would one find a+b+c?
Given 3a+b+2c=3,a+3b+2c=1, how do find 2a+c?
If 3a/5=2b/3=7c/2, then what is a:b:c?
2a+3b+4c=35………….(1)
3a+5b+7c=30………….(2)
So…….. the question is just easy one. There are so many methods to solve it. But I think this will be the easiest one.
First.. Multiply equation (1) by 2
4a+6b+8c=70……(3)
Then substrate equation (2) from it
It will give.;
a+b+c=40.
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2a + 3b + 4c = 35 ………………..(1)
3a + 5b + 7c = 30…………………(2)
(2) - (1): a + 2b +3c = -5………….(3)
(1) - (3): a + b + c = 40………….(Answer)
Multiply 5 in equation 1 and 3 in equation 2 and then subtract both of them
You will get a relation in a and c. i.e. a-c=85.
Again multiply 7 in equation 1 and 4 in equation 2 again subtract both of them
Equation obtained is 2a+b=125. Now write 2a as a+a
Keep one a as it is and substitue other a as c+85
Final answer would be a+b+c=40.
If 2a +3b=6 and a+b=7, what is the value of a&b?
If 3a+5b3a−5b=5 then what is the ratio of a:b ?
What is the value of a and b if 2a×3b=72?
What is (3a-b)(3a-b)+a(4b-9a)-b(b+5a)?
If a=4 and b=3, what is 3a+4b?
To start, double the first equation
2(2a+3b+4c)=(2×35)⟹4a+6b+8c=70
Then subtract the second equation from that.
4a+6b+8c−3a−5b−7c=70−30
⟹(4a−3a)+(6b−5b)+(8c−7c)=40
a+b+c=40
a+b+c+a+2b+3c=35
3a+5b+7c=30
a+b+c+2(a+2a+3c)=30
a+b+c+2(35-(a+b+c))=30
70–30=2(a+b+c)-(a+b+c)
40=a+b+c
Hope this gives answer
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Since there are 3 unknowns - a, b and c and there are only two equations you cannot find the values of the 3 unknowns and so you cannot determine a+b+c.
Add both the equations you will get the third one and solve them
a+b+c=2*35 - 30 = 40.
40
40
40
I need to solve for the three unknowns a, b, and c in the following equations. 3a - 5c = -9, 2a + 7b = 11, a + b + c = 6. The answer is (2, 1, 3), but how do I get there?
What are a, b, and c if 2a + 3b + 4c = 10?
If 3a+2b+4c=26 and 6b+4a+2c=48, then how would one find a+b+c?
Given 3a+b+2c=3,a+3b+2c=1, how do find 2a+c?
If 3a/5=2b/3=7c/2, then what is a:b:c?
If 2a +3b=6 and a+b=7, what is the value of a&b?
If 3a+5b3a−5b=5 then what is the ratio of a:b ?
What is the value of a and b if 2a×3b=72?
What is (3a-b)(3a-b)+a(4b-9a)-b(b+5a)?
If a=4 and b=3, what is 3a+4b?
What is 2a+6b-3 (a+3b) (a+3b)?
What is the HCF of 1 and 2?
If a/b=3/4, then what is the value of 7a-4b:3a+b?
If a : b = 2 : 3, then what is (4a - b) : (2a + 3b)?
If a=6 and b=5, what is the value of 3a+2b ?
Step-by-step explanation:
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