Question

27. Two springs have force constants K1 and K2, where K1> K2. On which spring more work is done if
(i) they are stretched by the same force (ii) They are stretched by the same amount.
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Answer 1

Answer:

Explanation:energy stored by a spring is 1/2kx(square)......(~1)

Force =kx........(2)

We need to find relation between energy and force

F/k=x....substituting this in equation (1)

E=1/2k(f/k)square

E=F(square)/2k

So from here E inversely props to k

Now it's easy

Try to answer on your own and then check this answers

Case 1

K1>K2

So E1<E2 for same force {E invs props to k}

If k increases E decreases for same force

Case 2

K1>K2

We need to use equation 1

So E1>E2 for same elongation { E props to 1/2kx}

If k increases E increases

Answer 2

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