Question

27. Value of the resistance R in the figure is

(1) 6 Ω
(2) 8Ω
(3) 10 Ω
(4) 12 Ω​

Answer 1

Answer:

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Answer 2

Answer: 6ohm

Explanation:

Since all of these are in series so, their eq resistance becomes

4+2+R=6+R

And current is 1A

By. V=IR

12=1×(6+R)

r=6ohm

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