Question

27. What least number should be subtracted from 1860, so that the remainder when divided by 7, 12 and 16 is 5? (b) 180 (c) 185 (d) 1680 (a) 175​

Answer 1

Answer:

172 is the answer.

Step-by-step explanation:

First we have to find such smallest number which will be divisible by all three given divisors i.e. 7, 12 and 16.

Hence, taking LCM, we get 336 as such number.

Any multiple of 336 will be divisible by 7, 12 and 16. Now we need to get such multiple of 336 that is less than 1856 and also closest to it. Here,

336 x 5 = 1680 is such number.

Since we want such a number which will give a remainder of 4 when divided by 7,12 and 16, we need to add 4 to 1680 and thus we get 1684.

Now, we need to find the number required to be subtracted from 1856, that will be

1856 - 1684 = 172

Hence, the answer. Hope it is helpful.

Answer 2

Answer:

172 is the answer.

Step-by-step explanation:

First we have to find such smallest number which will be divisible by all three given divisors i.e. 7, 12 and 16.

Hence, taking LCM, we get 336 as such number.

Any multiple of 336 will be divisible by 7, 12 and 16. Now we need to get such a multiple of 336 that is less than 1856 and also closest to it. Here,

336 x 5 = 1680 is such number.

Since we want such a number that will give a remainder of 4 when divided by 7,12 and 16, we need to add 4 to 1680 and thus we get 1684.

Now, we need to find the number required to be subtracted from 1856, which will be

1856 - 1684 = 172

Hence, the answer. Hope it is helpful.