Physics, asked by hardikkumar16, 6 months ago

27. Why banking of road is necessary? Obtain formula for maximum permissible speed of a vehicle
on a banked road in the presence of friction with suitable diagram.​

Answers

Answered by soumyabehl
0

Explanation:

Banking of road means raising the outer edge of the road with respect to inner edge so that the road makes an angle with the horizontal.

When a vehicle moves along a curve, the force of friction provides the necessary centripetal force. But this force has a limit = μmg.When the speed of the vehicle increases beyond this maximum value, the banking of roads is necessary so that the component of normal reaction of the road towards the centre provides the necessary centripetal force.

From the figure, for vertical equilibrium :

Total upwards force = total downwards force

Ncosθ=mg+fsinθ

mg=Ncosθ−fsinθ...(1)

As the forces Nsinθ,fcosθ provide the necessary centripetal force.

r

mv

2

=Nsinθ+fcosθ...(2)

Thus dividing (2) by (1),

mg

r

mv

2

=

Ncosθ−fsinθ

Nsinθ+fcosθ

As f=μ

s

N

Thus,

rg

v

2

=

cosθ−μ

s

sinθ

sinθ+μ

s

cosθ

=

1−μ

s

tanθ

tanθ+μ

s

=

1−tanλtanθ

tanθ+tanλ

=tan(θ+λ)

v=

rgtan(θ+λ)

where tanλ=μ

s

solution

Answered by sunakat483
0

Answer:

Obtain an expression for the maximum speed with which a vehicle can safely negotiate a curved road banked at an angle θ, considering the friction is negligible. ... Hence, when the road is banked, it is easier for a car to take the turn at a higher speed.

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