27/x-2 +31/y+3 =85; 31/x-2+ 27/y+3 =89
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Answered by
136
Hii friend,
27/X-2 + 31/Y+3 = 85.....(1)
31/X-2 + 27/Y+3 = 89
Let 1/X-2 = U and 1/Y+3 = V
Putting 1/X-2 = U in and 1/Y+3 = V in equation (1) and (2)
27/X-2 + 31/Y+3= 85
27U + 31V = 85......(3)
31U + 27V = 89.......(4)
From equation (3) we get,
27U +31V = 85
27U = 85-31V
U = 85-31V/27........(5)
Putting the value of U in equation (4)
31U + 27V = 89
31 × (85-31V/27) + 27V = 89
2635 - 961V /27 + 27V = 89
2635-961V + 729V ÷ 27 = 89
2635-961V + 729V = 89×27
2635 - 232V = 2403
-232V = 2403 - 2635
-232V = -232
V = -232/-232
V = 1
Putting the value of V in equation (5)
U = 85-31V/27
U = 85-31×1/27 => 85-31/27 = 54/27
U = 2
Therefore,
U = 2 and V = 1
Therefore,
U= 1/X-2
2 = 1/X-2
2(X-2) = 1
2X -4 = 1
2X = 1+4
2X = 5
X = 5/2
And,
V = 1/Y+3
1 = 1/Y+3
Y+3 = 1
Y = 1-3
Y = -2
Hence,
Y = -2 and X = 5/2
HOPE IT WILL HELP YOU..... :-)
27/X-2 + 31/Y+3 = 85.....(1)
31/X-2 + 27/Y+3 = 89
Let 1/X-2 = U and 1/Y+3 = V
Putting 1/X-2 = U in and 1/Y+3 = V in equation (1) and (2)
27/X-2 + 31/Y+3= 85
27U + 31V = 85......(3)
31U + 27V = 89.......(4)
From equation (3) we get,
27U +31V = 85
27U = 85-31V
U = 85-31V/27........(5)
Putting the value of U in equation (4)
31U + 27V = 89
31 × (85-31V/27) + 27V = 89
2635 - 961V /27 + 27V = 89
2635-961V + 729V ÷ 27 = 89
2635-961V + 729V = 89×27
2635 - 232V = 2403
-232V = 2403 - 2635
-232V = -232
V = -232/-232
V = 1
Putting the value of V in equation (5)
U = 85-31V/27
U = 85-31×1/27 => 85-31/27 = 54/27
U = 2
Therefore,
U = 2 and V = 1
Therefore,
U= 1/X-2
2 = 1/X-2
2(X-2) = 1
2X -4 = 1
2X = 1+4
2X = 5
X = 5/2
And,
V = 1/Y+3
1 = 1/Y+3
Y+3 = 1
Y = 1-3
Y = -2
Hence,
Y = -2 and X = 5/2
HOPE IT WILL HELP YOU..... :-)
RazaTaha11:
Thanks
Answered by
77
Answer:
I hope it helps
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