Math, asked by SUPERMATHS, 11 months ago

27/x-2+31/y+3=85 ; 31/x-2+27/y+3=89
Solve the following simultaneous equation

Answers

Answered by monty842311
8

Answer:

Step-by-step explanation:

27/x-2+31/y+3=85 ; 31/x-2+27/y+3=89

1/(x-2) = a, 1/(y+3) = b

27a + 31b = 85................1

31a + 27b = 89................2

multiply

eq1×31

eq2×27

837a + 961b = 2635  .............3

837a + 729b = 2403  ............4

eq3-eq4

232b = 232

b=1

put b=1 in eq1

27a + 31×1 = 85

27a = 85-31

27a = 54

a=2

now

1/x-2 = 2

2x-4=1

2x=5

x=5/2

1/y+3 = 1

y+3 = 1

y = -2

therefore

x= 2.5 , y= -3

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