Math, asked by samragursimran30, 8 months ago

27(x^3y^2z^2+x^2y^3z^2+x^2y^2z^3)÷45x^2y^2z^2​

Answers

Answered by memithra2003
3

Answer:

3(x+y+z)/5

Step-by-step explanation:

27(x^3y^2z^2 + x^2y^3z^2 + x^2y^2z^3)/45x^2y^2z^2

=27(x^2y^2z^2)(x+y+z) / 45(x^2y^2z^2)

=3(x+y+z)/5

Answered by Anonymous
0

Go through the attachment .......

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