Question

27(x+y)^3+8(2x-y)^3

Please answer it fastly...​

Answer 1

$\huge\underline\bold{answer}$

27(x+y)3+8(2x−y)3

Above terms can be written as,

33(x+y)3+23(2x−y)3

(3(x+y))3+(2(x−y))3

We know that,a3+b3=(a+b)(a2−ab+b2)

Where,a=3(x+y),b=2(x−y)

=[3(x+y)+2(2x−y)][(3(x+y))3−(3(x+y)×2(2x−y))+(2(2x−y))2]

=[3x+3y+4x−2y][9(x+y)2−6(x+y)(2x−y)+4(2x−y)2]

=(7x−y)[9(x2+y2+2xy)

Answer 2

It can be written as,

${}^{3} (x + y)^{3} + {2}^{3} (2x - y) ^{3}$

$(3(x + y)^{3} + (2(x - y)^{3}$