Question

27 x³ + y³+ 2³-9xyz ..(plz follow me...)​

Answer 1

Answer:

(3x)^3+y^3+z^3-9xyz

Step-by-step explanation:

3x^3 + y^3+z^3-3x*y*z

using identity

a^3+b^3+c^3-3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)

Put a=3x,b=y,c=z

(3x+y+z)(9x^2+y^2+z^2-3xy-yz-zx)