(273/8)^2/3-(1/4)^-2+5^0
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Answered by
2
Hi ,
I think there's an error in the question.
It may be like this.
( 343/8 )^2/3 - ( 1/4 )^-2 + 5^0
***************************************
By exponential laws :
1 ) a^0 = 1
2 ) ( a/b )^-n = ( b/a )ⁿ
3 ) aⁿ/bⁿ = ( a/b )ⁿ
4 ) ( a^m )^n = a^mn
*****************************************
= ( 7³/2³ )^2/3 - 4² + 1
= [ ( 7/2 )³ ]^2/3 - 16 + 1
= ( 7/2 )^3×2/3 - 15
= ( 7/2 )² - 15
= 49/4 - 15
= ( 49 - 60 )/15
= -11/15
I hope this helps you.
: )
I think there's an error in the question.
It may be like this.
( 343/8 )^2/3 - ( 1/4 )^-2 + 5^0
***************************************
By exponential laws :
1 ) a^0 = 1
2 ) ( a/b )^-n = ( b/a )ⁿ
3 ) aⁿ/bⁿ = ( a/b )ⁿ
4 ) ( a^m )^n = a^mn
*****************************************
= ( 7³/2³ )^2/3 - 4² + 1
= [ ( 7/2 )³ ]^2/3 - 16 + 1
= ( 7/2 )^3×2/3 - 15
= ( 7/2 )² - 15
= 49/4 - 15
= ( 49 - 60 )/15
= -11/15
I hope this helps you.
: )
Answered by
0
Answer:
373.171875
Step-by-step explanation:
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