Question

27540=2log2+4log3+log5+log7

Answer 1

Hey there,

Here is your answer,

Since,we know log mn = log m + log n

So,

2Log 2+4log 3+log 5+log 17

=log 2^2 + log 3^4 + log 5 + log 17

= log 4 +log 81 +log 5 +log 17

=log (4x81x5x17)

=log 27540

Hope it will help...

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