Question

27a^3-125b^3
factorise​

Answer 1

Answer:

Answer is given below...

Step-by-step explanation:

There is an identity used for this...

$a^3-b^3=(a-b)(a^2+ab+b^2)$

So,

$27a^3-125b^2\\=(3a)^3-(5b)^3\\=(3a-5b)[(3a)^2+(3a)(5b)+(5b)^2]\\=(3a-5b)(9a^2+15ab+25b^2)$

Hope it helps!

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