27a^3-8b^3 factorise using sutaible identity
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Answered by
6
Answer:
(3a - 2b) (9a^2 + 4b^2 + 6ab)
Step-by-step explanation:
27a^3 - 8b^3
= (3a)^3 - (2b)^3
= (3a - 2b) [(3a)^2 + (2b)^2 + 3a*2b]
= (3a - 2b) (9a^2 + 4b^2 + 6ab)
Answered by
1
Step-by-step explanation:
It 27a^ 3 -8b^ 3 -c^ 3 aab , exists c
then find
underline 4a-3b \\ underline = ?
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