Question

27a^3-b^3+8c^3+18abc

Answer 1

$27 {a}^{3} - {b}^{3} + 8 {c}^{3} - 18abc \\ \\ = ({3a})^{3} - ({b})^{3} + ({2c})^{3} - 3 \times 3a \times ( - b) \times 2c \\ \\= (3a - b + 2c)(9 {a}^{2} + {b}^{2} + 4 {c}^{2} + 3ab - 2bc + 6ca)$

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