27a^3-b^3+c^3+9abc factorise
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27a³-b³+c³+9abc
=>(3a)³+(-b)³+(c)³-3(3a)(-b)(c)
=>(3a-b+c)(9a²+b²+c²+3ab+bc-3ca)
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27a³-b³+c³+9abc
=>(3a)³+(-b)³+(c)³-3(3a)(-b)(c)
=>(3a-b+c)(9a²+b²+c²+3ab+bc-3ca)
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1
Answer:
27a^3-b^3+c^3+9abc
Step-by-step explanation:
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