Question

27a2-48b2 factorise​

Answer 1

Step-by-step explanation:

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Answer 2

Given: 27a²-48b²²

To find: Factorise

Step-by-step explanation:

1) Take 3 common in both of them, this will make it: 3(9a²-16b²)

2) Make 9a² (3a)² and 16b² as (4b)² then we will get:
    3[(3a)²-(4b)²]

Using a²-b² = (a+b)(a-b)

We get: 3(3a+4b)(3a-4b)

Hence, 27a²-48b² = 3(3a+4b)(3a-4b)