Question

27a³+1/64b³+27a²/4b+9a/16b²

Answer 1

We know that, (a+b)³=a³+b³+3a²b+3ab²

on comparing with formula we get,

27a³ + 1/64b³ + 27a²/4b + 9a/16b² = (3a)³ + ((1/4)b)³ + 3.(3a)².(1/4b) + 3.(3a)(1/4)²

                                                         = (3a + (1/4)b)³

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Answer 2

Answer:

*EXPLANATION*

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