27a³-27a²b+9ab²-b³ factorise using suitable identities
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Answer:
Answer is (3a -b)³ .
27a³ - 27a²b + 9ab² - b³ = (3a - b)³
Using Identity VI ,
(a - b)³ = a³ - 3a²b + 3ab² - b³
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