Math, asked by andehannah14gmailcom, 1 month ago

27a³+64b³factorise with the identity x³+y³=(x+y)(x²-xy+y²

Answers

Answered by Kamehamehaaa

2

27a³- 64b³

(3a)³+ (4b)³= (3a+4b)(9a²+12ab-16b²)

Answered by singhanshika1102

1

Step-by-step explanation:

(3a+4b)(9a^2-12ab+16b^2)

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