27g of Al will react completely with how much mass of O2 to produce Al2O3?
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0
Answer:
Answer is 102
Explanation:
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Answer:
✌ the balanced reaction is
4Al + 3O₂ -----→ 2Al₂O₃
There for 4 mole of Al 3 moles of O₂
so for 1 mole Al 3/4 mole O₂
27 g Al means 1 mole so 3/4 mole O₂ is needed
ie 3/4 x 32 = 24 g
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