Question

27g of Al will react completely with how much mass of O² to produce Al²O³
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Answer 1

Answer:

4Al + 3O2 --> 2Al2O3

4×27g Al gives---> 3×32g O2

1g " " ----> 3×32/4×27

27g " " ---->

$\frac{3 \times 32}{4 \times 27} \times 27$

=24.g O2