27g of al will react completely with oxygen equals to
Answers
Answered by
19
The balanced equation for the given reaction is:
4 Al + 3 O2 --------> 2 Al2O3
Atomic mass of Al = 27g
Atomic mass of O2 = 2 � 16 = 32g
Mole ratio of aluminium and oxygen can be given as:
Al : O2
4 : 3
1 : 3/4
Mass of O2 required = 3/4 � 32 =24g
Answered by
14
Balance chemical eq.
4Al+3O2-------->2Al2O3
Mass Al = 27g
Mass O2= 16×2
32g
Therefore the ratio of Al and oxygen
Al. : O2
4. : 3
1. : 3/4
Hence 3/4× 32
24g of oxygen
Good luck
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