Question

27g of aluminium (Al=27g).​

Answer 1

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• The balance equation is

4Al+3O2

→2AlO3

• Atomic mass of Al=27 g

• Atomic mass of O 2

=2×16=32 g

Mole ratio , Al:O2

=4:3

=1:43

• Mass of O required =

43 ×32=24 g

Hence , 24 g of oxygen is required

Answer 2

I hope it will helps you.....