27g of aluminum will react completely with how much mass of O2 to produce Al2o3
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27 g of Al= 1 mole of Al
Balance this equation
4Al + 3O2 → 2Al2O3
Mole ratio
Al : O2
4 : 3
1 : 3/4
Mass of O2 = 3/4 × 32 = 24g
Balance this equation
4Al + 3O2 → 2Al2O3
Mole ratio
Al : O2
4 : 3
1 : 3/4
Mass of O2 = 3/4 × 32 = 24g
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