27p3-1/216-9p2/2+1/4p
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(a+b)
3
=a
3
+b
3
+3a
2
b+3ab
2
and (a−b)
3
=a
3
+b
3
−3a
2
b−3ab
2
(i) 8a
3
+b
3
+12a
2
b+6ab
2
=(2a)
3
+(b)
3
+3(2a)
2
(b)+3(2a)(b)
2
=(2a+b)
3
(ii) 8a
3
+b
3
−12a
2
b−6ab
2
=(2a)
3
+(b)
3
−3(2a)
2
(b)−3(2a)(b)
2
=(2a−b)
3
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