Math, asked by krishnendukumar2110, 8 months ago

27tan^2 theta +3cot^2 theta find the minimum value??

Answers

Answered by shreyankabaragadagi
0

Answer:

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Answered by Anonymous
0

You can use the concept of AM >= GM to solve this

take numbers as tan^2theta,tan^2theta,tan^2theta….27 times and cot^2theta,cot^2theta,cot^2theta

So we will get

[27 tan^2 theta + 3 cot^2 theta]/ 30 >= {27tan^2 theta* 3 cot^2 theta}1/2

27 tan^2 theta + 3 cot^2 theta >= 9 * 30

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