Question

27x^3+125 factorise​

Answer 1

Answer:

Rewrite 27x3 27 x 3 as (3x)3 ( 3 x ) 3 . Rewrite 125 as 53 . Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=3x a = 3 x and b=5 .

Answer 2

Answer:

27x^3+125 factorise

3 x 3 x 3 x 3^3+5x5x5

3^3x3^3+5^3

[ 3^6+5^3 ]