Question

(27x^3 +3x^2-2x +8) ÷ (3x- 2)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :$(27x^3 +3x^2-2x +8)\div (3x- 2)$

To Find : Solve

Solution:

Dividend: $27x^3+3x^2-2x+8$

Divisor : $3x-2$

Formula :$Dividend = Divisor \times Quotient + Remainder$

$27x^3+3x^2-2x+8=(3x-2) \times (9x^2) +(21x^2-2x)\\27x^3+3x^2-2x+8=(3x-2) \times (9x^2+7x) +(12x+8)\\27x^3+3x^2-2x+8=(3x-2) \times (9x^2+7x+4) +16$

So,$27x^3+3x^2-2x+8 \div (2x-2) =(9x^2+7x+4)+\frac{16}{(3x-2)}$