Math, asked by sarilsaifi, 10 months ago

27x^3+8y^3 find 3x+2y=4 and xy=8​

Answers

Answered by mitajoshi11051976
0

 = 27 {x}^{3}  + 8 {y}^{3}  \\   = {( 3x) }^ {3} +  {(2y)}^{3}  \\   =  {(3x + 2y)}^{3}  \\  =  {?}^{?}


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