Question

27x^3+y^3+z^3-9xyz factorise this​

Answer 1

See in the attachment given below

hope it helps you

Answer 2

Answer and explanation:

$27x {}^{3} + y {}^{3} + z {}^{3} - 9xyz$

$= (3x) { }^{3} + y {}^{3} + z {}^{3} - 9xyz$

$= (3x + y + z)((3x) {}^{2} + y {}^{2} + z {}^{2} - (3x)(y) - (y)(z) - (z)(3x))$

$= (3x + y + z)(9x {}^{2} + y {}^{2} + z {}^{2} - 3xy - yz - 3zx)$

This factorisation uses the formula

$a {}^{3} + b {}^{3} + c {}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)$

I hope this helps. :)